Solid Geometry

The geometry of three-dimensional figures — prisms, pyramids, spheres, cylinders, and cones — and their properties.

Common 3-D solids
CubeV = s³SA = 6s²hrConeV = ⅓πr²hSA = πr² + πrlhlTriangular PrismV = (½bh) × lSq. PyramidV = ⅓s²hSA = s² + 2sl
Definition

Solid geometry is the geometry of three-dimensional shapes. While flat (2D) geometry deals with areas and lengths, solid geometry adds a third dimension and introduces volume (the space inside) and surface area (the total area of the outer faces).

Common 3D shapes:

  • Prism: two identical parallel bases connected by rectangular faces (e.g., a box, a triangular prism)
  • Pyramid: a polygonal base tapering to a point (apex)
  • Cylinder: circular base, curved side, circular top
  • Cone: circular base tapering to a point
  • Sphere: all points equidistant from the centre in 3D

Each shape has its own volume formula, but they follow patterns: prisms and cylinders multiply base area by height; pyramids and cones are one-third of that.

Volume of a rectangular prism

A rectangular box is 44 cm long, 33 cm wide, and 55 cm tall.

V=length×width×height=4×3×5=60 cm3V = \text{length} \times \text{width} \times \text{height} = 4 \times 3 \times 5 = 60 \text{ cm}^3

The surface area (the total area of all six faces):

SA=2(4×3)+2(4×5)+2(3×5)=24+40+30=94 cm2SA = 2(4 \times 3) + 2(4 \times 5) + 2(3 \times 5) = 24 + 40 + 30 = 94 \text{ cm}^2

Try it

A cylindrical can has radius 33 cm and height 1010 cm. Find its volume and surface area. Use π3.14\pi \approx 3.14.

Solution

V=πr2h=π(3)2(10)=90π282.6 cm3V = \pi r^2 h = \pi (3)^2 (10) = 90\pi \approx 282.6 \text{ cm}^3

SA=2πr2+2πrh=2π(9)+2π(3)(10)=18π+60π=78π245.0 cm2SA = 2\pi r^2 + 2\pi r h = 2\pi(9) + 2\pi(3)(10) = 18\pi + 60\pi = 78\pi \approx 245.0 \text{ cm}^2

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